Dave Chase wrote:
Ok, here goes.
If you have push only mag force then there is an opposite force from the direction of travel.
If you have pull/push mag (tube) force, much of the force is already in balance. (not taking in effect of atmosphere inside the barrel) Ie each booster ring/section pulls then pushes the object forward.
If you have an object doint the work as a pusher and puller, it also is in balance with it self.
But the objects it is using for the push/pulling must be of greater force (or mass) that the objects energy or they will be effected by the push/pull.
Last a rail gun is different than a mag accelerator, as already mentioned. But that aside, I understood what you were asking.
maybe I'm missing something here but,
regardless of whether the ring/section is pushing -or- pulling, its reaction will be in the opposite direction of the bullet. If its pushing -and- pulling simultaneously, it won't accelerate the bullet as the forces would cancel out, right?
Don't all the force vectors added together have to equal zero to maintain conservation of momentum?
What would happen if you launched a volkswagen ... still no recoil at all? So an asteroid miner could launch iron ingots to a orbital factory without changing his own course/orbit?
balls in atmosphere... spin might not be just to counteract drop, but to curve a shot in sideways too ( within reason )... or how about sliders or knuckleballs or 'english' applied to riccochets .
would that be enough of an advantage to offset the energy losses from having worse aero-efficiencies? ( which would get worse still as velocity and thus reynold's numbers drop down... actually, I forget, but I think there's a fairly steep drop off on the drag coefficient for a sphere below a certain reynold's value )